LOJ 1387 - Setu

In this problem, you will be given T test cases. Each test case begins with an integer N followed by N lines. Each line contains either of the strings:

• donate K, where K is an integer ranging from 100 to 100000 inclusive, or
• report

Note that, both of T and N can be at most 100.

Now, keep an integer variable sum with initial value as 0. When you receive the string donate K, your task is to add K to the sum. And, when you receive the string report, your task is to print out the value of the sum.

The problem is pretty straightforward. However, some people might find it difficult to get an Accepted verdict. The reason could be one of the following:

1. Failing to provide proper output format
2. Missing new line on each line

If you are still stuck with this problem, check the codes below:

C++

#include <bits/stdc++.h>
using namespace std;

int main() {
  int T, N, K, sum;
  string operation;
  cin >> T;
  for (int i = 1; i <= T; i++) {
    cin >> N; sum = 0;
    cout << "Case " << i << ":\n";
    for (int j = 1; j <= N; j++) {
      cin >> operation;
      if (operation == "donate") {
        cin >> K;
        sum += K;
      } else {
        cout << sum << "\n";
      }
    }
  }
  return 0;
}

Java

package com.loj.volume;

import java.util.Scanner;

class Setu {
  public static void main(String[] args) throws Exception {
    int T, N, sum;
    String operation;
    Scanner input = new Scanner(System.in);
    T = input.nextInt();
    for (int i = 1; i <= T; i++) {
      N = input.nextInt(); sum = 0;
      System.out.printf("Case %d:\n", i);
      for (int j = 1; j <= N; j++) {
        operation = input.next();
        if (operation.equals("donate")) {
          sum += input.nextInt();
        } else {
          System.out.printf("%d\n", sum);
        }
      }
    }
  }
}

Tutorial source